Indexerror pop index out of range in python

pop( 21), it looks for the 21st item in the list. Since there are not that many items, you get an IndexError. remove( 21) instead of pop( ) to. 引数を省略して位置を指定しない場合は、 末尾( 最後) の要素を削除する。 print( l. pop( ) ) # 9 print( l) # [ 1, 2, 3, 5, 6, 7]. source: list_ remove_ item. 存在しない位置を指定 するとエラーになる。 IndexError: pop index out of range. There are problems with your code, for example in this selection they are all present: result. append( left[ 0] ) left = left. This should be: result. The problems are: Python lists use 0- based indexing ' s safer to write this as card = deck. pop( randint( 0, len( deck) - 1) ). Though it' s faster if you save that value somewhere. But that also points to a problem that your deck has a problem. Are you for loops in the deck creation.

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  • Video:Range indexerror python

    Index indexerror python

    Im getting an Index Error on Line 28 that says ' IndexError: pop index out of range' I have no idea how to fix this. I' m also open to other suggestions for making my code better. By the way my program isn' t finished yet. Navin Kabra, Python' s my primary language for development for last 2 years. And if you' ve already popped at least one value out of this list earlier, List. pop( 8) is going to fail with an IndexError because List does not have 9. What does the error: " IndexError: list index out of range" imply in the following piece of code? pop( ) takes the index of an element to remove, not the item to remove. remove( ) instead. You are removing elements from the list as you are iterating over them, this causes the list to shrink in size during iteration, but the iteration would still continue for the length of the original list, hence causing such InderError. l= range( 8) > > > l [ 0, 1, 2, 3, 4, 5, 6, 7] > > > l. pop( 4) # item at index 4 4 > > > l [ 0, 1, 2, 3, 5, 6, 7] > > > l. pop( - 1) # item at end. l= [ ] > > > try:.

    except IndexError:. print " sorry - - can' t pop that". sorry - - can' t pop that.